Решите неравенство: x+35-6x^2<=0.

Ответ:

\[x + 35 - 6x^{2} \leq 0\]

\[6x^{2} - x - 35 \geq 0\]

\[D = 1 + 840 = 841 = 29^{2}\]

\[x_{1} = \frac{1 + 29}{12} = \frac{30}{12} = \frac{5}{2} = 2,5;\]

\[x_{2} = \frac{1 - 29}{12} = - \frac{28}{12} = - \frac{7}{3} = - 2\frac{1}{3}.\]

\[\left( x + 2\frac{1}{3} \right)(x - 2,5) \geq 0\]

\[x \leq - 2\frac{1}{3};x \geq 2,5.\]

\[Ответ:x \leq - 2\frac{1}{3};x \geq 2,5.\]