Решите неравенство: 2x^2+5x-7<0.

Ответ:

\[2x^{2} + 5x - 7 < 0\]

\[D = 25 + 56 = 81\]

\[x_{1} = \frac{- 5 + 9}{4} = 1;\]

\[x_{2} = \frac{- 5 - 9}{4} = - \frac{14}{4} = - \frac{7}{2} = - 3,5;\]

\[2(x + 3,5)(x - 1) < 0\]

\[- 3,5 < x < 1.\]

\[Ответ:\ - 3,5 < x < 1.\]