Вопрос:

Решите неравенство: -2x^2+13x-6<=0.

Ответ:

\[- 2x^{2} + 13x - 6 \leq 0\]

\[2x^{2} - 13x + 6 \geq 0\]

\[D = 169 - 48 = 121\]

\[x_{1} = \frac{13 + 11}{4} = 6;\]

\[x_{2} = \frac{13 - 11}{4} = \frac{2}{4} = 0,5;\]

\[2(x - 0,5)(x - 6) \geq 0\]

\[x \leq 0,5;\ \ x \geq 6.\]

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