Представьте в виде рациональной дроби ((3x-y)/(y+1))/((3x+y)/(y-1)+(3-y/x)/(3x/y-1).

Ответ:

\[\frac{\frac{3x - y}{y} + 1}{\frac{3x + y}{y} - 1} + \frac{3 - \frac{y}{x}}{\frac{3x}{y} - 1} = \frac{x + y}{x}\]

\[1.\ \ \frac{3x - y}{y} + 1^{\backslash y} = \frac{3x - y + y}{y} =\]

\[= \frac{3x}{y}\]

\[2.\ \ \frac{3x + y}{y} - 1^{\backslash y} = \frac{3x + y - y}{y} =\]

\[= \frac{3x}{y}\]

\[3.\ \ \frac{3x}{y} \cdot \ \frac{y}{3x} = 1\]

\[4.\ \ 3^{\backslash x} - \frac{y}{x} = \ \frac{3x - y}{y}\]

\[5.\ \frac{3x}{y} - 1^{\backslash y} = \ \frac{3x - y}{y}\]

\[6.\ \ \frac{3x - y}{x} \cdot \frac{y}{3x - y} = \frac{y}{x}\]

\[7.\ \ 1^{\backslash x} + \frac{y}{x} = \frac{x + y}{x}\]