Найдите множество решений неравенства 3x/2-(x-3)/8+(2x+2)/12≥0.

\[\frac{3x}{2} - \frac{x - 3}{8} + \frac{2x + 2}{12} \geq 0\ \ \ \ \ \ | \cdot 24\]

\[36x - 3(x - 3) + 2(2x + 2) \geq 0\]

\[36x - 3x + 9 + 4x + 4 \geq 0\]

\[27x \geq - 13\]

\[x \geq - \frac{13}{27}\]

\[Ответ:x \in \left\lbrack - \frac{13}{27}; + \infty \right).\]