ГДЗ по математике 5 класс Мерзляк ФГОС Задание 1017

 

\[\boxed{\mathbf{1017\ (1017)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 18,56\ :3,2 = 5,8\ \left( \frac{м^{3}}{ч} \right) -\]

\[скорость\ первого\ насоса.\]

\[2)\ 22,32\ :3,6 = 6,2\ \left( \frac{м^{3}}{ч} \right) -\]

\[скорость\ второго\ насоса.\]

\[3)\ 6,2 - 5,8 = 0,4\ \left( \frac{м^{3}}{ч} \right) -\]

\[скорость\ второго\ насоса\ \]

\[на\ столько\ больше.\]

\[Ответ:скорость\ второго\ \]

\[насоса\ больше\ на\ 0,4\ \frac{м^{3}}{ч}.\]

\[\boxed{\mathbf{1017}\mathbf{.}\mathbf{\ }}\]

\[1)\ 5\frac{7^{\backslash 5}}{8} + 6\frac{3^{\backslash 4}}{10} = 5\frac{35}{40} + 6\frac{12}{40} =\]

\[= 11\frac{47}{40} = 12\frac{7}{40}\]

\[2)\ 6\frac{3^{\backslash 9}}{8} + 2\frac{5^{\backslash 8}}{9} = 6\frac{27}{72} + 2\frac{40}{72} =\]

\[= 8\frac{67}{72}\]

\[3)\ 1\frac{8^{\backslash 2}}{21} + 4\frac{3^{\backslash 3}}{14} + 2\frac{2^{\backslash 6}}{7} =\]

\[= 1\frac{16}{42} + 4\frac{9}{42} + 2\frac{12}{42} = 7\frac{37}{42}\]

\[\boxed{\mathbf{1018}\mathbf{.}\mathbf{\ }}\]

\[1)\ 8\frac{9}{14} - 3\frac{3^{\backslash 2}}{7} = 8\frac{9}{14} - 3\frac{6}{14} =\]

\[= 5\frac{3}{14}\]

\[2)\ 7\frac{5^{\backslash 2}}{12} - 3\frac{7}{24} = 7\frac{10}{24} - 3\frac{7}{24} =\]

\[= 4\frac{3}{24} = 4\frac{1}{8}\]

\[3)\ 12\frac{11^{\backslash 3}}{12} - 5\frac{13^{\backslash 2}}{18} =\]

\[= 12\frac{33}{36} - 5\frac{26}{36} = 7\frac{7}{36}\]

Задание 1019

\[\boxed{\mathbf{1019}\mathbf{.}\mathbf{\ }}\]

\[1)\ 3\frac{1}{12} - \frac{1^{\backslash 2}}{6} = 2\frac{13}{12} - \frac{2}{12} =\]

\[= 2\frac{11}{12}\]

\[2)\ 8\frac{7^{\backslash 2}}{30} - 2\frac{9^{\backslash 3}}{20} = 8\frac{14}{60} - 2\frac{27}{60} =\]

\[= 7\frac{74}{60} - 2\frac{27}{60} = 5\frac{47}{60}\]

\[3)\ 7\frac{10^{\backslash 2}}{51} - 4\frac{21^{\backslash 3}}{34} =\]

\[= 7\frac{20}{102} - 4\frac{63}{102} =\]

\[= 6\frac{\ 122}{102} - 4\frac{63}{102} = 2\frac{59}{102}\ \]

\[4)\ 5\frac{1^{\backslash 2}}{4} - 1\frac{3}{8} = 5\frac{2}{8} - 1\frac{3}{8} =\]

\[= 4\frac{10}{8} - 1\frac{3}{8} = 3\frac{7}{8}\]