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МатематикаГДЗ по геометрии 7 класс Атанасян ФГОС Задание 935
Задание 935
\[\boxed{\mathbf{935.ОК\ ГДЗ - домашка\ на}\ 5}\]
| \[A\] | \[(0;0)\] | \[(x; - 3)\] | \[(6;1,5)\] | \[(a;b)\] | \[(1;2)\] |
|---|---|---|---|---|---|
| \[B\] | \[(1;1)\] | \[(2; - 7)\] | \[(3;1)\] | \[(a + c;d + b)\] | \[(1;2)\] |
| \[\overrightarrow{\text{AB}}\] | \[(1;1)\] | \[\{ 5;y\}\] | \[\{ - 3; - \frac{1}{2}\}\] | \[\{ c;d\}\] | \[\{ 0;0\}\] |
\[\overrightarrow{\text{AB}} = \left\{ 2 - x;\ - 7 - ( - 3) \right\} =\]
\[= \left\{ 5;y \right\}:\]
\[2 - x = 5 \Longrightarrow x = - 3;\]
\[- 4 = y \Longrightarrow y = - 4.\]
\[\boxed{\mathbf{935.еуроки - ответы\ на\ пятёрку}}\]
\[\textbf{а)}\ Параллелограмм\ MNPQ.\]
\[Коллинеарные:\ \]
\[\overrightarrow{\text{NP}}\ и\ \overrightarrow{\text{MQ}};\ \overrightarrow{\text{MN}}\ и\ \overrightarrow{\text{PQ}};\ \overrightarrow{\text{PN}}\ и\ \overrightarrow{\text{QM}};\]
\[\ \overrightarrow{\text{MN}}\ и\ \overrightarrow{\text{QP}};\ \overrightarrow{\text{NP}}\ и\ \overrightarrow{\text{QM}};\ \]
\[\overrightarrow{\text{PN}}\ и\ \overrightarrow{\text{MQ}};\ \overrightarrow{\text{NM}}\ и\ \overrightarrow{\text{PQ}};\ \overrightarrow{\text{NM}}\ и\ \overrightarrow{\text{QP}}.\]
\[Сонаправленные:\ \]
\[\overrightarrow{\text{NP}}\ и\ \overrightarrow{\text{MQ}};\ \overrightarrow{\text{PN}}\ и\ \overrightarrow{\text{QM}};\ \overrightarrow{\text{NM}}\ и\ \overrightarrow{\text{PQ}};\]
\[\ \overrightarrow{\text{MN}}\ и\ \overrightarrow{\text{QP}}\text{.\ }\]
\[Противоположно\ \]
\[направленные:\ \ \]
\[\overrightarrow{\text{NP}}\ и\ \overrightarrow{\text{QM}};\ \overrightarrow{\text{PN}}\ и\ \overrightarrow{\text{MQ}};\ \overrightarrow{\text{NM}}\ и\ \overrightarrow{\text{QP}};\]
\[\ \overrightarrow{\text{MN}}\ и\ \overrightarrow{\text{PQ}}\text{.\ \ \ }\]
\[\textbf{б)}\ Трапеция\ ABCD\ \]
\[с\ основаниями\ \text{AD\ }и\ \text{BC.}\]
\[Коллинеарные:\ \]
\[\overrightarrow{\text{BC}}\ и\ \overrightarrow{\text{AD}};\ \overrightarrow{\text{BC}}\ и\ \overrightarrow{\text{DA}};\ \overrightarrow{\text{CB}}\ и\ \overrightarrow{\text{DA}};\ \]
\[\overrightarrow{\text{CB}}\ и\ \overrightarrow{\text{AD}}.\]
\[Сонаправленные:\ \]
\[\overrightarrow{\text{BC}}\ и\ \overrightarrow{\text{AD}};\ \overrightarrow{\text{CB}}\ и\ \overrightarrow{\text{DA}}\text{.\ }\]
\[Противоположно\ \]
\[направленные:\ \]
\[\overrightarrow{\text{BC}}\ и\ \overrightarrow{\text{DA}};\ \overrightarrow{\text{CB}}\ и\ \overrightarrow{\text{AD}}.\]
\[\textbf{в)}\ Треугольник\ FGH.\]
\[Нет\ коллинеарных\ векторов.\]
