Алгебра
Английский
Биология
География
Геометрия
Русский
История
Обществознание
Физика
Химия
Информатика
Литература
МатематикаГДЗ по алгебре и начала математического анализа 11 класс Колягин Задание 921
Задание 921
\[1)\ \left( x^{2} - 4 \right) \bullet \log_{0,5}x > 0\]
\[x^{2} - 4 > 0\]
\[(x + 2)(x - 2) > 0\]
\[x < - 2;\ \ \ x > 2.\]
\[\log_{0,5}x > 0\]
\[x < 1.\]
\[Область\ определения:\]
\[x > 0.\]
\[Ответ:\ \ x \in (1;\ 2).\]
\[2)\ (3x - 1) \bullet \log_{2}x > 0\]
\[3x - 1 > 0\]
\[3x > 1\]
\[x > \frac{1}{3}.\]
\[\log_{2}x > 0\]
\[x > 1.\]
\[Область\ определения:\]
\[x > 0.\]
\[Ответ:\ \ x \in \left( 0;\ \frac{1}{3} \right) \cup (1;\ + \infty).\]
\[3)\log_{7}{\log_{\frac{1}{3}}\frac{x^{2} + |x| - 30}{x + 6}} < 0\]
\[\log_{\frac{1}{3}}\frac{x^{2} + |x| - 30}{x + 6} < 1\]
\[\frac{x^{2} + |x| - 30}{x + 6} > \frac{1}{3}\]
\[\frac{3\left( x^{2} + |x| - 30 \right) - (x + 6)}{3(x + 6)} > 0\]
\[\frac{3x^{2} + \left( 3|x| - x \right) - 96}{x + 6} > 0\]
\[x \geq 0:\]
\[\frac{3x^{2} + 2x - 96}{x + 6} > 0\]
\[D = 4 + 1152 = 1156\]
\[x_{1} = \frac{- 2 - 34}{2 \bullet 3} = - 6;\]
\[\ x_{2} = \frac{- 2 + 34}{2 \bullet 3} = \frac{16}{3};\]
\[(x + 6)\left( x - \frac{16}{3} \right) > 0\]
\[x < - 6;\ \ \ x > \frac{16}{3}.\]
\[x \leq 0:\]
\[\frac{3x^{2} - 4x - 96}{x + 6} > 0\]
\[D = 16 + 1152 = 1168\]
\[x = \frac{4 \pm \sqrt{1168}}{2 \bullet 3} = \frac{4 \pm 2\sqrt{292}}{2 \bullet 3} =\]
\[= \frac{2 \pm \sqrt{292}}{3};\]
\[- 6 < x < \frac{2 - \sqrt{292}}{3}\]
\[x > \frac{2 + \sqrt{292}}{3}.\]
\[Область\ определения:\]
\[\log_{\frac{1}{3}}\frac{x^{2} + |x| - 30}{x + 6} > 0\]
\[\frac{x^{2} + |x| - 30}{x + 6} < 1\]
\[\frac{x^{2} + |x| - 30 - x - 6}{x + 6} < 0\]
\[\frac{x^{2} + \left( |x| - x \right) - 36}{x + 6} < 0.\]
\[x \geq 0:\]
\[\frac{x^{2} - 36}{x + 6} < 0\]
\[\frac{(x + 6)(x - 6)}{x + 6} < 0\]
\[x < 6;\ \ \ x \neq - 6.\]
\[x \leq 0:\]
\[\frac{x^{2} - 2x - 36}{x + 6} < 0\]
\[D = 4 + 144 = 148\]
\[x = \frac{2 \pm \sqrt{148}}{2} = \frac{2 \pm 2\sqrt{37}}{2} =\]
\[= 1 \pm \sqrt{37};\]
\[x < - 6;\]
\[1 - \sqrt{37} < x < 1 + \sqrt{37}.\]
\[Ответ:\ \ \]
\[x \in \left( 1 - \sqrt{37};\ \frac{2 - \sqrt{292}}{3} \right) \cup \left( \frac{16}{3};\ 6 \right).\]
